What is the answer to 5^{2x-1}=\sqrt[3]{25^{x^2-1/4}} ?

The answer to 5^{2x-1}=\sqrt[3]{25^{x^2-1/4}} is x= 5/2 ,x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5^{2x-1}=\sqrt[3]{25^{x^2-1/4}}

x = \frac{5}{2}, x = \frac{1}{2}

Decimal Notation

x = 2.5, x = 0.5

Solution steps

Apply exponent rules

2 x - 1 = \frac{2}{3} (x^{2} - \frac{1}{4})

Solve

2 x - 1 = \frac{2}{3} (x^{2} - \frac{1}{4}) : x = \frac{5}{2}, x = \frac{1}{2}

x = \frac{5}{2}, x = \frac{1}{2}

2^{x - 1} + 2^{x - 2} + 2^{x - 3} + 2^{x - 4} = 960

6^{x - 7} - 8 = 40

1 1^{x + 6} = 3^{x}

4 x e^{x} = 2

2^{\frac{1}{2}} = 4 e^{- \frac{t}{0.00001}}

What is the answer to 5^{2x-1}=\sqrt[3]{25^{x^2-1/4}} ?
The answer to 5^{2x-1}=\sqrt[3]{25^{x^2-1/4}} is x= 5/2 ,x= 1/2
Solve for x: 5^{2x-1}=\sqrt[3]{25^{x^2-1/4}}
The solution is x= 5/2 ,x= 1/2