What is the answer to 2^{x-1}+2^{x-2}+2^{x-3}+2^{x-4}=960 ?

The answer to 2^{x-1}+2^{x-2}+2^{x-3}+2^{x-4}=960 is x=10

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2^{x-1}+2^{x-2}+2^{x-3}+2^{x-4}=960

2^{x - 1} + 2^{x - 2} + 2^{x - 3} + 2^{x - 4} = 960

x = 10

Solution steps

2^{x - 1} + 2^{x - 2} + 2^{x - 3} + 2^{x - 4} = 960

Factor

2^{x - 1} + 2^{x - 2} + 2^{x - 3} + 2^{x - 4} : 15 \cdot 2^{x - 4}

15 \cdot 2^{x - 4} = 960

Divide both sides by

15

2^{x - 4} = 64

Apply exponent rules

x - 4 = 6

Solve

x - 4 = 6 : x = 10

x = 10

6^{x - 7} - 8 = 40

1 1^{x + 6} = 3^{x}

4 x e^{x} = 2

2^{\frac{1}{2}} = 4 e^{- \frac{t}{0.00001}}

3^{20 - x} = 9

What is the answer to 2^{x-1}+2^{x-2}+2^{x-3}+2^{x-4}=960 ?
The answer to 2^{x-1}+2^{x-2}+2^{x-3}+2^{x-4}=960 is x=10
Solve for x: 2^{x-1}+2^{x-2}+2^{x-3}+2^{x-4}=960
The solution is x=10