What is the answer to solvefor t,A=P(1+r/n)^{nt} ?

The answer to solvefor t,A=P(1+r/n)^{nt} is t=(ln(A/P))/(nln(1+r/n))

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solvefor t,A=P(1+r/n)^{nt}

solve for

t, A = P (1 + \frac{r}{n})^{n t}

t = \frac{ln ( \frac{A}{P} )}{n ln ( 1 + \frac{r}{n} )}

Solution steps

A = P (1 + \frac{r}{n})^{n t}

Switch sides

P (1 + \frac{r}{n})^{n t} = A

Divide both sides by

P

(1 + \frac{r}{n})^{n t} = \frac{A}{P}

Apply exponent rules

n t ln (1 + \frac{r}{n}) = ln (\frac{A}{P})

Solve

n t ln (1 + \frac{r}{n}) = ln (\frac{A}{P}) : t = \frac{ln ( \frac{A}{P} )}{n ln ( 1 + \frac{r}{n} )}

t = \frac{ln ( \frac{A}{P} )}{n ln ( 1 + \frac{r}{n} )}

1 - e^{- x} = 0

9^{x} = 100

(\frac{1}{5})^{x} \times 12 5^{x + 1} = 4

(\frac{1}{2})^{4 x - 2} = 2^{x - 2}

1 8^{2 x} \cdot 3^{- 2 x} = 6

What is the answer to solvefor t,A=P(1+r/n)^{nt} ?
The answer to solvefor t,A=P(1+r/n)^{nt} is t=(ln(A/P))/(nln(1+r/n))