What is the answer to \sqrt[3]{3^{x-5}}=27 ?

The answer to \sqrt[3]{3^{x-5}}=27 is x=14

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\sqrt[3]{3^{x-5}}=27

x = 14

Solution steps

Apply exponent rules

(x - 5) \frac{1}{3} = 3

Solve

(x - 5) \frac{1}{3} = 3 : x = 14

x = 14

5^{x} = 50

2^{2 x} - 3 \cdot 2^{x} = - 2

6 4^{- x + 26} = 12 8^{x}

5^{x} = 6^{x - 1}

3 e^{2 x} - 4 e^{- 2 x} = 5

What is the answer to \sqrt[3]{3^{x-5}}=27 ?
The answer to \sqrt[3]{3^{x-5}}=27 is x=14
Solve for x: \sqrt[3]{3^{x-5}}=27
The solution is x=14