What is the answer to 3^{2x}=4^{2-x} ?

The answer to 3^{2x}=4^{2-x} is x=(2ln(2))/(ln(6))

Solve for x: 3^{2x}=4^{2-x}

The solution is x=(2ln(2))/(ln(6))

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3^{2 x} = 4^{2 - x}

x = \frac{2 ln ( 2 )}{ln ( 6 )}

Decimal Notation

x = 0.77370 \dots

Solution steps

3^{2 x} = 4^{2 - x}

Apply exponent rules

2 x ln (3) = (2 - x) ln (4)

Solve

2 x ln (3) = (2 - x) ln (4) : x = \frac{2 ln ( 2 )}{ln ( 6 )}

x = \frac{2 ln ( 2 )}{ln ( 6 )}

9^{3 x - 8} = 8 1^{2 x}

2 7^{x + 5} = 24 3^{x - 1}

e^{- 4 x} - 4 e^{- 4 x} x = 0

5^{x - 4} = 3^{2 x}

3^{2 x} (3^{2 x - 1})^{3} = 9

What is the answer to 3^{2x}=4^{2-x} ?
The answer to 3^{2x}=4^{2-x} is x=(2ln(2))/(ln(6))
Solve for x: 3^{2x}=4^{2-x}
The solution is x=(2ln(2))/(ln(6))