What is the answer to solvefor x,4^{x+1}+4^x=160 ?

The answer to solvefor x,4^{x+1}+4^x=160 is x= 5/2

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solvefor x,4^{x+1}+4^x=160

solve for

x, 4^{x + 1} + 4^{x} = 160

x = \frac{5}{2}

Solution steps

4^{x + 1} + 4^{x} = 160

Factor

4^{x + 1} + 4^{x} : 5 \cdot 4^{x}

5 \cdot 4^{x} = 160

Divide both sides by

5

4^{x} = 32

Apply exponent rules

2 x = 5

Solve

2 x = 5 : x = \frac{5}{2}

x = \frac{5}{2}

2^{4} = 8^{x}

\frac{8 1 ^{3 x + 2}}{24 3 ^{- x}} = 3^{4}

2^{x} + 2^{x + 3} + 2^{x - 1} = \frac{19}{4}

2 \times 9^{x} = 162

7^{x + 5} = 4

What is the answer to solvefor x,4^{x+1}+4^x=160 ?
The answer to solvefor x,4^{x+1}+4^x=160 is x= 5/2