What is the answer to (81^{3x+2})/(243^{-x)}=3^4 ?

The answer to (81^{3x+2})/(243^{-x)}=3^4 is x=-4/17

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(81^{3x+2})/(243^{-x)}=3^4

\frac{8 1 ^{3 x + 2}}{24 3 ^{- x}} = 3^{4}

x = - \frac{4}{17}

Solution steps

\frac{8 1 ^{3 x + 2}}{24 3 ^{- x}} = 3^{4}

Apply exponent rules

4 (3 x + 2) + 5 x = 4

Solve

4 (3 x + 2) + 5 x = 4 : x = - \frac{4}{17}

x = - \frac{4}{17}

Verify Solutions:

x = - \frac{4}{17}

True

The solution is

x = - \frac{4}{17}

2^{x} + 2^{x + 3} + 2^{x - 1} = \frac{19}{4}

2 \times 9^{x} = 162

7^{x + 5} = 4

9^{x} - 4 \times 3^{x} + 3 = 0

\frac{1000}{1 + 39 e ^{- 0.42 x}} = 630

What is the answer to (81^{3x+2})/(243^{-x)}=3^4 ?
The answer to (81^{3x+2})/(243^{-x)}=3^4 is x=-4/17
Solve for x: (81^{3x+2})/(243^{-x)}=3^4
The solution is x=-4/17