What is the answer to 125^{m+3}=0.04^{2m+2} ?

The answer to 125^{m+3}=0.04^{2m+2} is m=-13/7

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125^{m+3}=0.04^{2m+2}

12 5^{m + 3} = 0.0 4^{2 m + 2}

m = - \frac{13}{7}

Decimal Notation

m = - 1.85714 \dots

Solution steps

12 5^{m + 3} = 0.0 4^{2 m + 2}

12 5^{m + 3} = (\frac{1}{25})^{2 m + 2}

Apply exponent rules

3 (m + 3) = - 2 (2 m + 2)

Solve

3 (m + 3) = - 2 (2 m + 2) : m = - \frac{13}{7}

m = - \frac{13}{7}

9^{x} + 3^{1 + 2 x} = 20

9^{x} + 3^{1 + 2 x} = 50

9^{2 x + 5} = 2 7^{x}

4^{3 x - 1} = 3 2^{x}

- 11 e^{- x} = 0

What is the answer to 125^{m+3}=0.04^{2m+2} ?
The answer to 125^{m+3}=0.04^{2m+2} is m=-13/7
Solve for m: 125^{m+3}=0.04^{2m+2}
The solution is m=-13/7