What is the answer to 5^{x-1}=3^{2x+1} ?

The answer to 5^{x-1}=3^{2x+1} is x=(ln(15))/(ln(5)-2ln(3))

Solve for x: 5^{x-1}=3^{2x+1}

The solution is x=(ln(15))/(ln(5)-2ln(3))

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5^{x - 1} = 3^{2 x + 1}

x = \frac{ln ( 15 )}{ln ( 5 ) - 2 ln ( 3 )}

Decimal Notation

x = - 4.60719 \dots

Solution steps

5^{x - 1} = 3^{2 x + 1}

Apply exponent rules

(x - 1) ln (5) = (2 x + 1) ln (3)

Solve

(x - 1) ln (5) = (2 x + 1) ln (3) : x = \frac{ln ( 15 )}{ln ( 5 ) - 2 ln ( 3 )}

x = \frac{ln ( 15 )}{ln ( 5 ) - 2 ln ( 3 )}

201 \cdot 2^{x} = 67

4^{5 x + 1} = 16

8^{x - 1} = \frac{1}{16 2}

2^{x + 3} - 2^{x + 1} = 12

What is the answer to 5^{x-1}=3^{2x+1} ?
The answer to 5^{x-1}=3^{2x+1} is x=(ln(15))/(ln(5)-2ln(3))
Solve for x: 5^{x-1}=3^{2x+1}
The solution is x=(ln(15))/(ln(5)-2ln(3))