What is the answer to 3^{4x}=7^{2-5x} ?

The answer to 3^{4x}=7^{2-5x} is x=(2ln(7))/(4ln(3)+5ln(7))

Solve for x: 3^{4x}=7^{2-5x}

The solution is x=(2ln(7))/(4ln(3)+5ln(7))

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3^{4 x} = 7^{2 - 5 x}

x = \frac{2 ln ( 7 )}{4 ln ( 3 ) + 5 ln ( 7 )}

Decimal Notation

x = 0.27554 \dots

Solution steps

3^{4 x} = 7^{2 - 5 x}

Apply exponent rules

4 x ln (3) = (2 - 5 x) ln (7)

Solve

4 x ln (3) = (2 - 5 x) ln (7) : x = \frac{2 ln ( 7 )}{4 ln ( 3 ) + 5 ln ( 7 )}

x = \frac{2 ln ( 7 )}{4 ln ( 3 ) + 5 ln ( 7 )}

2^{3 k - 1} \cdot 2^{5 k - 7} = 16

4^{2 x} = 62 5^{3 x + 5}

\frac{1}{2} = 1 - e^{- 2 x}

7^{x - 1} = 49

7 \cdot 9^{x} - 2 \cdot 3^{2 x + 1} = 90 - 3^{x}

What is the answer to 3^{4x}=7^{2-5x} ?
The answer to 3^{4x}=7^{2-5x} is x=(2ln(7))/(4ln(3)+5ln(7))
Solve for x: 3^{4x}=7^{2-5x}
The solution is x=(2ln(7))/(4ln(3)+5ln(7))