What is the answer to 6^{1+x}= 1/(36^{4x+2)} ?

The answer to 6^{1+x}= 1/(36^{4x+2)} is x=-5/9

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6^{1+x}= 1/(36^{4x+2)}

6^{1 + x} = \frac{1}{3 6 ^{4 x + 2}}

x = - \frac{5}{9}

Decimal

x = - 0.55555 \dots

Solution steps

6^{1 + x} = \frac{1}{3 6 ^{4 x + 2}}

Apply exponent rules

1 + x = 2 (- 4 x - 2)

Solve

1 + x = 2 (- 4 x - 2) : x = - \frac{5}{9}

x = - \frac{5}{9}

Verify Solutions:

x = - \frac{5}{9}

True

The solution is

x = - \frac{5}{9}

e^{x + π} = π^{x + e}

2^{2 x} - 2^{x + 1} + 2^{0} = 0

e^{2 x + 3} = 3

2^{3 x + 1} - 2^{3 x - 1} = 96

2^{x} = 16000

What is the answer to 6^{1+x}= 1/(36^{4x+2)} ?
The answer to 6^{1+x}= 1/(36^{4x+2)} is x=-5/9
Solve for x: 6^{1+x}= 1/(36^{4x+2)}
The solution is x=-5/9