What is the answer to 2^{3x+1}-2^{3x-1}=96 ?

The answer to 2^{3x+1}-2^{3x-1}=96 is x=2

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2^{3x+1}-2^{3x-1}=96

2^{3 x + 1} - 2^{3 x - 1} = 96

x = 2

Solution steps

2^{3 x + 1} - 2^{3 x - 1} = 96

Apply exponent rules

3 x = 6

Solve

3 x = 6 : x = 2

x = 2

2^{x} = 16000

105 0^{x} + 105 0^{x + 1} + 105 0^{x + 2} = 2021

4^{x} = 26

4^{x} = 21

4 \times 7^{x} = 4

What is the answer to 2^{3x+1}-2^{3x-1}=96 ?
The answer to 2^{3x+1}-2^{3x-1}=96 is x=2
Solve for x: 2^{3x+1}-2^{3x-1}=96
The solution is x=2