What is the answer to log_{2}(10^x)=4 ?

The answer to log_{2}(10^x)=4 is x=(4ln(2))/(ln(10))

Solve for x: log_{2}(10^x)=4

The solution is x=(4ln(2))/(ln(10))

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lo g_{2} (1 0^{x}) = 4

x = \frac{4 ln ( 2 )}{ln ( 10 )}

Decimal Notation

x = 1.20411 \dots

Solution steps

lo g_{2} (1 0^{x}) = 4

Rewrite the equation with

1 0^{x} = u

lo g_{2} (u) = 4

Solve

lo g_{2} (u) = 4 : u = 16

u = 16

Substitute back

u = 1 0^{x},

solve for

x

Solve

1 0^{x} = 16 : x = \frac{4 ln ( 2 )}{ln ( 10 )}

x = \frac{4 ln ( 2 )}{ln ( 10 )}

3^{x + 2} + 3^{x} = 810

4^{x - x^{2}} = \frac{1}{6 4 ^{x}}

x, \frac{e ^{2 x + 1}}{5} = yz

15 e^{5 x} = 5

62 \cdot 1 0^{x} = 40

What is the answer to log_{2}(10^x)=4 ?
The answer to log_{2}(10^x)=4 is x=(4ln(2))/(ln(10))
Solve for x: log_{2}(10^x)=4
The solution is x=(4ln(2))/(ln(10))