What is the answer to 7^{2+x}=1.4*5^{2+x} ?

The answer to 7^{2+x}=1.4*5^{2+x} is x=(ln(5/7))/(ln(7)-ln(5))

Solve for x: 7^{2+x}=1.4*5^{2+x}

The solution is x=(ln(5/7))/(ln(7)-ln(5))

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7^{2 + x} = 1.4 \cdot 5^{2 + x}

x = \frac{ln ( \frac{5}{7} )}{ln ( 7 ) - ln ( 5 )}

Decimal Notation

x = - 1

Solution steps

7^{2 + x} = 1.4 \cdot 5^{2 + x}

Apply exponent rules

(2 + x) ln (7) = ln (1.4) + (2 + x) ln (5)

Solve

(2 + x) ln (7) = ln (1.4) + (2 + x) ln (5) : x = \frac{ln ( \frac{5}{7} )}{ln ( 7 ) - ln ( 5 )}

x = \frac{ln ( \frac{5}{7} )}{ln ( 7 ) - ln ( 5 )}

9 \times 8 1^{1 - 2 x} = 2 7^{2 - x}

1 0^{x} = 121

x^{2} e^{x} + 2 x e^{x} = 0

6^{- 2 x} = 6^{3}

3 8^{x} = 65536

What is the answer to 7^{2+x}=1.4*5^{2+x} ?
The answer to 7^{2+x}=1.4*5^{2+x} is x=(ln(5/7))/(ln(7)-ln(5))
Solve for x: 7^{2+x}=1.4*5^{2+x}
The solution is x=(ln(5/7))/(ln(7)-ln(5))