What is the answer to 10^{2x+9}=6*7^{x-4} ?

The answer to 10^{2x+9}=6*7^{x-4} is x=(ln(6)-4ln(7)-9ln(10))/(2ln(10)-ln(7))

Solve for x: 10^{2x+9}=6*7^{x-4}

The solution is x=(ln(6)-4ln(7)-9ln(10))/(2ln(10)-ln(7))

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1 0^{2 x + 9} = 6 \cdot 7^{x - 4}

x = \frac{ln ( 6 ) - 4 ln ( 7 ) - 9 ln ( 10 )}{2 ln ( 10 ) - ln ( 7 )}

Decimal Notation

x = - 10.04608 \dots

Solution steps

1 0^{2 x + 9} = 6 \cdot 7^{x - 4}

Apply exponent rules

(2 x + 9) ln (10) = ln (6) + (x - 4) ln (7)

Solve

(2 x + 9) ln (10) = ln (6) + (x - 4) ln (7) : x = \frac{ln ( 6 ) - 4 ln ( 7 ) - 9 ln ( 10 )}{2 ln ( 10 ) - ln ( 7 )}

x = \frac{ln ( 6 ) - 4 ln ( 7 ) - 9 ln ( 10 )}{2 ln ( 10 ) - ln ( 7 )}

y, x = 4 - 3^{2 y - 1}

5^{x} = 37

6^{x + 1} = 7^{6 x - 1}

- 1 (1 - 2^{x}) = 2094

4^{x} \cdot 3^{2 x} = 6

What is the answer to 10^{2x+9}=6*7^{x-4} ?
The answer to 10^{2x+9}=6*7^{x-4} is x=(ln(6)-4ln(7)-9ln(10))/(2ln(10)-ln(7))
Solve for x: 10^{2x+9}=6*7^{x-4}
The solution is x=(ln(6)-4ln(7)-9ln(10))/(2ln(10)-ln(7))