What is the answer to -1(1-2^x)=2180 ?

The answer to -1(1-2^x)=2180 is x=(ln(2181))/(ln(2))

Solve for x: -1(1-2^x)=2180

The solution is x=(ln(2181))/(ln(2))

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- 1 (1 - 2^{x}) = 2180

x = \frac{ln ( 2181 )}{ln ( 2 )}

Decimal Notation

x = 11.09077 \dots

Solution steps

- 1 \cdot (1 - 2^{x}) = 2180

Divide both sides by

- 1

1 - 2^{x} = - 2180

Move

1

to the right side

- 2^{x} = - 2181

Divide both sides by

- 1

2^{x} = 2181

Apply exponent rules

x ln (2) = ln (2181)

Solve

x ln (2) = ln (2181) : x = \frac{ln ( 2181 )}{ln ( 2 )}

x = \frac{ln ( 2181 )}{ln ( 2 )}

2^{3 x - 1} = 2 \cdot 3^{2 - 3 x}

6 e^{1 - x} = 25

x, 2^{x + 1} = \frac{1}{2 ^{2 x + 3}}

3 2^{x} = (\frac{1}{128})^{x - 4}

4^{x + 1} + 4^{x + 2} - 320 = 0

What is the answer to -1(1-2^x)=2180 ?
The answer to -1(1-2^x)=2180 is x=(ln(2181))/(ln(2))
Solve for x: -1(1-2^x)=2180
The solution is x=(ln(2181))/(ln(2))