What are the solutions to the equation 2d^{243}d=84 ?

The solutions to the equation 2d^{243}d=84 are d=\sqrt[244]{42},d=-\sqrt[244]{42}

Find the zeros of 2d^{243}d=84

The zeros of 2d^{243}d=84 are d=\sqrt[244]{42},d=-\sqrt[244]{42}

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2 d^{243} d = 84

Decimal Notation

d = 1.01543 \dots, d = - 1.01543 \dots

Solution steps

2 d^{243} d = 84

Simplify

2 d^{244} = 84

Divide both sides by

2

\frac{2 d ^{244}}{2} = \frac{84}{2}

d^{244} = 42

For

x^{n} = f (a)

, n is even, the solutions are

s^{3} + 5 s^{2} + 24 s + 20

\frac{4 x}{3} x^{8} = 20

x^{4} - 4 x^{2} - 45 = 0

x^{4} - 2 x^{3} - 5 x^{2} + 8 x + 4 = 0

3 x^{3} + 81 = 0

What are the solutions to the equation 2d^{243}d=84 ?
The solutions to the equation 2d^{243}d=84 are d=\sqrt[244]{42},d=-\sqrt[244]{42}
Find the zeros of 2d^{243}d=84
The zeros of 2d^{243}d=84 are d=\sqrt[244]{42},d=-\sqrt[244]{42}