What are the solutions to the equation x^5+15x+62=0 ?

The solutions to the equation x^5+15x+62=0 are x=-2

Find the zeros of x^5+15x+62=0

The zeros of x^5+15x+62=0 are x=-2

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x^{5} + 15 x + 62 = 0

x = - 2

Solution steps

x^{5} + 15 x + 62 = 0

Factor

x^{5} + 15 x + 62 : (x + 2) (x^{4} - 2 x^{3} + 4 x^{2} - 8 x + 31)

(x + 2) (x^{4} - 2 x^{3} + 4 x^{2} - 8 x + 31) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x^{4} - 2 x^{3} + 4 x^{2} - 8 x + 31 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{4} - 2 x^{3} + 4 x^{2} - 8 x + 31 = 0 :

No Solution for

x \in R

The solution is

x = - 2

20 x^{3} + 12 x^{2} - 5 x - 3 = 0

x^{4} - 10 x^{3} + 120 x + 144 = 0

x^{3} - 3 x^{2} + 4 x - 4

x^{3} - x^{2} - x - 15 = 0

x^{3} + 8 x^{2} + 9 x - 18

What are the solutions to the equation x^5+15x+62=0 ?
The solutions to the equation x^5+15x+62=0 are x=-2
Find the zeros of x^5+15x+62=0
The zeros of x^5+15x+62=0 are x=-2