What are the solutions to the equation roots-x^3+4x^2-5x+2 ?

The solutions to the equation roots-x^3+4x^2-5x+2 are x=1,x=2

Find the zeros of roots-x^3+4x^2-5x+2

The zeros of roots-x^3+4x^2-5x+2 are x=1,x=2

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roots

- x^{3} + 4 x^{2} - 5 x + 2

x = 1, x = 2

Solution steps

- x^{3} + 4 x^{2} - 5 x + 2

The roots are the intercepts with the x-axis

(y = 0)

- x^{3} + 4 x^{2} - 5 x + 2 = 0

Factor

- x^{3} + 4 x^{2} - 5 x + 2 : - (x - 1)^{2} (x - 2)

- (x - 1)^{2} (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = 1, x = 2

x^{4} - 4 x^{3} + 8 x^{2} - 16 x + 16

- 1 = m^{3}

x^{4} + 6 x^{3} + 17 x^{2} + 22 x + 14 = 0

x^{3} - 4 x - 8 = 0

x^{3} - 3 x^{2} - 4 x + 12

What are the solutions to the equation roots-x^3+4x^2-5x+2 ?
The solutions to the equation roots-x^3+4x^2-5x+2 are x=1,x=2
Find the zeros of roots-x^3+4x^2-5x+2
The zeros of roots-x^3+4x^2-5x+2 are x=1,x=2