What are the solutions to the equation 12x^3+24x^2-36x=0 ?

The solutions to the equation 12x^3+24x^2-36x=0 are x=0,x=1,x=-3

Find the zeros of 12x^3+24x^2-36x=0

The zeros of 12x^3+24x^2-36x=0 are x=0,x=1,x=-3

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12 x^{3} + 24 x^{2} - 36 x = 0

x = 0, x = 1, x = - 3

Solution steps

12 x^{3} + 24 x^{2} - 36 x = 0

Factor

12 x^{3} + 24 x^{2} - 36 x : 12 x (x - 1) (x + 3)

12 x (x - 1) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x + 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 3 = 0 : x = - 3

The solutions are

x = 0, x = 1, x = - 3

y, x^{3} + 4 x y^{2} - 27 = y^{4}

x^{6} - x^{3} - 2

z^{3} = (- 1 - 3 i)

x^{4} - 3 x^{3} + 3 x^{2} - 3 x + 2 = 0

x^{4} + 6 x^{3} - 3 x^{2} - 24 x - 4 = 0

What are the solutions to the equation 12x^3+24x^2-36x=0 ?
The solutions to the equation 12x^3+24x^2-36x=0 are x=0,x=1,x=-3
Find the zeros of 12x^3+24x^2-36x=0
The zeros of 12x^3+24x^2-36x=0 are x=0,x=1,x=-3