What are the solutions to the equation z^3=(-1-sqrt(3)i) ?

The solutions to the equation z^3=(-1-sqrt(3)i) are

Find the zeros of z^3=(-1-sqrt(3)i)

The zeros of z^3=(-1-sqrt(3)i) are

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z^{3} = (- 1 - 3 i)

Solution steps

z^{3} = (- 1 - 3 i)

Remove parentheses:

(a) = a

z^{3} = - 1 - 3 i

For

z^{n} = a

the solutions are

k = 0, 1, \dots, n - 1

For

n = 3, a = - 1 - 3 i

∣ a ∣ = 2

ar g (a) = \frac{π}{3} - π

Simplify

x^{4} - 3 x^{3} + 3 x^{2} - 3 x + 2 = 0

x^{4} + 6 x^{3} - 3 x^{2} - 24 x - 4 = 0

x^{4} - 6 x^{3} + 2 x^{2} + 26 x + 17

9 x^{3} + 9 x^{2} - x - 1 = 0

4 x^{3} - 2 x^{2} - 14 x - 48

What are the solutions to the equation z^3=(-1-sqrt(3)i) ?
The solutions to the equation z^3=(-1-sqrt(3)i) are
Find the zeros of z^3=(-1-sqrt(3)i)
The zeros of z^3=(-1-sqrt(3)i) are