What are the solutions to the equation x^3+x^2-12x-12=0 ?

The solutions to the equation x^3+x^2-12x-12=0 are x=-1,x=-2sqrt(3),x=2sqrt(3)

Find the zeros of x^3+x^2-12x-12=0

The zeros of x^3+x^2-12x-12=0 are x=-1,x=-2sqrt(3),x=2sqrt(3)

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x^{3} + x^{2} - 12 x - 12 = 0

x = - 1, x = - 23, x = 23

Decimal Notation

x = - 1, x = - 3.46410 \dots, x = 3.46410 \dots

Solution steps

x^{3} + x^{2} - 12 x - 12 = 0

Factor

x^{3} + x^{2} - 12 x - 12 : (x + 1) (x + 23) (x - 23)

(x + 1) (x + 23) (x - 23) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 23 = 0 or x - 23 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 23 = 0 : x = - 23

Solve

x - 23 = 0 : x = 23

The solutions are

x = - 1, x = - 23, x = 23

6 x^{3} + 25 x^{2} + 2 x - 8

3 x^{3} - 22 x^{2} + 5 x + 14 = 0

4 x^{3} - 8 x^{2} + 4 x = 0

x^{3} - x^{2} = 0

a^{6} = 30

What are the solutions to the equation x^3+x^2-12x-12=0 ?
The solutions to the equation x^3+x^2-12x-12=0 are x=-1,x=-2sqrt(3),x=2sqrt(3)
Find the zeros of x^3+x^2-12x-12=0
The zeros of x^3+x^2-12x-12=0 are x=-1,x=-2sqrt(3),x=2sqrt(3)