What are the solutions to the equation roots 6x^3+25x^2+2x-8 ?

The solutions to the equation roots 6x^3+25x^2+2x-8 are x=-4,x= 1/2 ,x=-2/3

Find the zeros of roots 6x^3+25x^2+2x-8

The zeros of roots 6x^3+25x^2+2x-8 are x=-4,x= 1/2 ,x=-2/3

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roots

6 x^{3} + 25 x^{2} + 2 x - 8

x = - 4, x = \frac{1}{2}, x = - \frac{2}{3}

Solution steps

6 x^{3} + 25 x^{2} + 2 x - 8

The roots are the intercepts with the x-axis

(y = 0)

6 x^{3} + 25 x^{2} + 2 x - 8 = 0

Factor

6 x^{3} + 25 x^{2} + 2 x - 8 : (x + 4) (2 x - 1) (3 x + 2)

(x + 4) (2 x - 1) (3 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or 2 x - 1 = 0 or 3 x + 2 = 0

Solve

x + 4 = 0 : x = - 4

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

The solutions are

x = - 4, x = \frac{1}{2}, x = - \frac{2}{3}

3 x^{3} - 22 x^{2} + 5 x + 14 = 0

4 x^{3} - 8 x^{2} + 4 x = 0

x^{3} - x^{2} = 0

a^{6} = 30

2 x^{4} - 6 x^{3} + 8 x = 0

What are the solutions to the equation roots 6x^3+25x^2+2x-8 ?
The solutions to the equation roots 6x^3+25x^2+2x-8 are x=-4,x= 1/2 ,x=-2/3
Find the zeros of roots 6x^3+25x^2+2x-8
The zeros of roots 6x^3+25x^2+2x-8 are x=-4,x= 1/2 ,x=-2/3