What are the solutions to the equation 1-5/2 x+2x^2-1/2 x^3=0 ?

The solutions to the equation 1-5/2 x+2x^2-1/2 x^3=0 are x=1,x=2

Find the zeros of 1-5/2 x+2x^2-1/2 x^3=0

The zeros of 1-5/2 x+2x^2-1/2 x^3=0 are x=1,x=2

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1 - \frac{5}{2} x + 2 x^{2} - \frac{1}{2} x^{3} = 0

x = 1, x = 2

Solution steps

1 - \frac{5}{2} x + 2 x^{2} - \frac{1}{2} x^{3} = 0

Multiply both sides by

2

- x^{3} + 4 x^{2} - 5 x + 2 = 0

Factor

- x^{3} + 4 x^{2} - 5 x + 2 : - (x - 1)^{2} (x - 2)

- (x - 1)^{2} (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = 1, x = 2

10 x^{3} - 39 x^{2} + 29 x - 6 = 0

4 x^{3} - 54 x^{2} + 240 x - 350 = 0

x^{3} - 64 = 0

y, 3 x^{3} + 9 x y^{2} = 5 x^{3}

y, x = 1 - y^{4}

What are the solutions to the equation 1-5/2 x+2x^2-1/2 x^3=0 ?
The solutions to the equation 1-5/2 x+2x^2-1/2 x^3=0 are x=1,x=2
Find the zeros of 1-5/2 x+2x^2-1/2 x^3=0
The zeros of 1-5/2 x+2x^2-1/2 x^3=0 are x=1,x=2