What are the solutions to the equation x^4+6x^3+8x^2-6x-9=0 ?

The solutions to the equation x^4+6x^3+8x^2-6x-9=0 are x=-1,x=1,x=-3

Find the zeros of x^4+6x^3+8x^2-6x-9=0

The zeros of x^4+6x^3+8x^2-6x-9=0 are x=-1,x=1,x=-3

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x^{4} + 6 x^{3} + 8 x^{2} - 6 x - 9 = 0

x = - 1, x = 1, x = - 3

Solution steps

x^{4} + 6 x^{3} + 8 x^{2} - 6 x - 9 = 0

Factor

x^{4} + 6 x^{3} + 8 x^{2} - 6 x - 9 : (x + 1) (x - 1) (x + 3)^{2}

(x + 1) (x - 1) (x + 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0 or x + 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

Solve

x + 3 = 0 : x = - 3

The solutions are

x = - 1, x = 1, x = - 3

x^{4} - 9 x^{3} + 27 x^{2} - 27 x = 0

x^{5} - 3 \cdot x^{2} + x + 1 = 0

x^{3} + 3 x^{2} - 18 x - 40 = 0

y, 25 x^{4} - 625 y - 500 = 0

x^{4} + 2 x^{2} - x + 8

What are the solutions to the equation x^4+6x^3+8x^2-6x-9=0 ?
The solutions to the equation x^4+6x^3+8x^2-6x-9=0 are x=-1,x=1,x=-3
Find the zeros of x^4+6x^3+8x^2-6x-9=0
The zeros of x^4+6x^3+8x^2-6x-9=0 are x=-1,x=1,x=-3