What are the solutions to the equation (x+4)(x^2-x+3)=0 ?

The solutions to the equation (x+4)(x^2-x+3)=0 are x=-4,x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2

Find the zeros of (x+4)(x^2-x+3)=0

The zeros of (x+4)(x^2-x+3)=0 are x=-4,x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2

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(x + 4) (x^{2} - x + 3) = 0

x = - 4, x = \frac{1}{2} + i \frac{11}{2}, x = \frac{1}{2} - i \frac{11}{2}

Solution steps

(x + 4) (x^{2} - x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x^{2} - x + 3 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x^{2} - x + 3 = 0 : x = \frac{1}{2} + i \frac{11}{2}, x = \frac{1}{2} - i \frac{11}{2}

The solutions are

x = - 4, x = \frac{1}{2} + i \frac{11}{2}, x = \frac{1}{2} - i \frac{11}{2}

(x^{2} - 2 x) (4 - x) = 0

x^{4} - x^{3} - 27 x + 27

6 x^{4} + 8 x^{3} = 0

2 x^{3} - 5 x^{2} + 8 x - 5

x^{2} 3 x + 2 = 0

What are the solutions to the equation (x+4)(x^2-x+3)=0 ?
The solutions to the equation (x+4)(x^2-x+3)=0 are x=-4,x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2
Find the zeros of (x+4)(x^2-x+3)=0
The zeros of (x+4)(x^2-x+3)=0 are x=-4,x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2