What are the solutions to the equation 4x^3-36x^2+104x-96=0 ?

The solutions to the equation 4x^3-36x^2+104x-96=0 are x=2,x=3,x=4

Find the zeros of 4x^3-36x^2+104x-96=0

The zeros of 4x^3-36x^2+104x-96=0 are x=2,x=3,x=4

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4 x^{3} - 36 x^{2} + 104 x - 96 = 0

x = 2, x = 3, x = 4

Solution steps

4 x^{3} - 36 x^{2} + 104 x - 96 = 0

Factor

4 x^{3} - 36 x^{2} + 104 x - 96 : 4 (x - 2) (x - 3) (x - 4)

4 (x - 2) (x - 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 3 = 0 or x - 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 3 = 0 : x = 3

Solve

x - 4 = 0 : x = 4

The solutions are

x = 2, x = 3, x = 4

z^{3} = (- 3 + i)

2 x^{3} + 2 x^{2} - 19 x + 20 = 0

3 x^{3} + 7 x^{2} - 4 = 0

y, x = y^{3} - 1

4 x^{3} + 12 x^{2} - 36 x = 0

What are the solutions to the equation 4x^3-36x^2+104x-96=0 ?
The solutions to the equation 4x^3-36x^2+104x-96=0 are x=2,x=3,x=4
Find the zeros of 4x^3-36x^2+104x-96=0
The zeros of 4x^3-36x^2+104x-96=0 are x=2,x=3,x=4