What are the solutions to the equation 5x^3-4x^2+4/5 x=0 ?

The solutions to the equation 5x^3-4x^2+4/5 x=0 are x=0,x=0.4

Find the zeros of 5x^3-4x^2+4/5 x=0

The zeros of 5x^3-4x^2+4/5 x=0 are x=0,x=0.4

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5 x^{3} - 4 x^{2} + \frac{4}{5} x = 0

x = 0, x = 0.4

Solution steps

5 x^{3} - 4 x^{2} + \frac{4}{5} x = 0

Factor

5 x^{3} - 4 x^{2} + \frac{4}{5} x : x (2.23606 \dots x - 0.89442 \dots)^{2}

x (2.23606 \dots x - 0.89442 \dots)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2.23606 \dots x - 0.89442 \dots = 0

Solve

2.23606 \dots x - 0.89442 \dots = 0 : x = 0.4

The solutions are

x = 0, x = 0.4

x^{3} + 3 x^{2} + 12 x + 4 = 0

x^{5} + x^{4} + x^{3} + x^{2} + x + 1

- 3 x^{3} - 4 x^{2} + 5 x + 2 = 0

4 x^{4} - 39 x^{3} + 54 x^{2} + 16 x

(x^{2} + 1) (4 + x) = 0

What are the solutions to the equation 5x^3-4x^2+4/5 x=0 ?
The solutions to the equation 5x^3-4x^2+4/5 x=0 are x=0,x=0.4
Find the zeros of 5x^3-4x^2+4/5 x=0
The zeros of 5x^3-4x^2+4/5 x=0 are x=0,x=0.4