What are the solutions to the equation roots x^4-4x^3+6x^2-4x+1 ?

The solutions to the equation roots x^4-4x^3+6x^2-4x+1 are x=1

Find the zeros of roots x^4-4x^3+6x^2-4x+1

The zeros of roots x^4-4x^3+6x^2-4x+1 are x=1

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roots

x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1

x = 1

Solution steps

x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1

The roots are the intercepts with the x-axis

(y = 0)

x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1 = 0

Factor

x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1 : (x - 1)^{4}

(x - 1)^{4} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0

Solve

x - 1 = 0 : x = 1

The solution is

x = 1

m^{6} + 3 m^{4} + 3 m^{2} + 1 = 0

3 x^{3} + 7 x^{2} + 147 x + 343 = 0

x^{3} - 6 x^{2} + 9 x + 5 = 0

z^{3} + 125 = 0

x^{4} - x - 2 = 0

What are the solutions to the equation roots x^4-4x^3+6x^2-4x+1 ?
The solutions to the equation roots x^4-4x^3+6x^2-4x+1 are x=1
Find the zeros of roots x^4-4x^3+6x^2-4x+1
The zeros of roots x^4-4x^3+6x^2-4x+1 are x=1