What are the solutions to the equation -x^3+x^2+x-2=-2 ?

The solutions to the equation -x^3+x^2+x-2=-2 are x=0,x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2

Find the zeros of -x^3+x^2+x-2=-2

The zeros of -x^3+x^2+x-2=-2 are x=0,x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2

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- x^{3} + x^{2} + x - 2 = - 2

x = 0, x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

Decimal Notation

x = 0, x = 1.61803 \dots, x = - 0.61803 \dots

Solution steps

- x^{3} + x^{2} + x - 2 = - 2

Move

2

to the right side

- x^{3} + x^{2} + x = 0

Factor

- x^{3} + x^{2} + x : - x (x^{2} - x - 1)

- x (x^{2} - x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} - x - 1 = 0

Solve

x^{2} - x - 1 = 0 : x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

The solutions are

x = 0, x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

x^{3} - 2 x + 1 = 0

x^{3} - 5 x^{2} - 7 x + 51 = 0

x^{5} = i

r^{5} + 5 r^{4} - 2 r^{3} - 10 r^{2} + r + 5 = 0

x^{3} - 3 x^{2} + 7 x - 5

What are the solutions to the equation -x^3+x^2+x-2=-2 ?
The solutions to the equation -x^3+x^2+x-2=-2 are x=0,x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2
Find the zeros of -x^3+x^2+x-2=-2
The zeros of -x^3+x^2+x-2=-2 are x=0,x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2