What are the solutions to the equation -k^3+3k-2=0 ?

The solutions to the equation -k^3+3k-2=0 are k=1,k=-2

Find the zeros of -k^3+3k-2=0

The zeros of -k^3+3k-2=0 are k=1,k=-2

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- k^{3} + 3 k - 2 = 0

k = 1, k = - 2

Solution steps

- k^{3} + 3 k - 2 = 0

Factor

- k^{3} + 3 k - 2 : - (k - 1)^{2} (k + 2)

- (k - 1)^{2} (k + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

k - 1 = 0 or k + 2 = 0

Solve

k - 1 = 0 : k = 1

Solve

k + 2 = 0 : k = - 2

The solutions are

k = 1, k = - 2

x^{6} = 100

x, x^{3} + x^{2} - 2 x - 1 = 0

3 x^{4} + 16 x^{3} + 32 x^{2} + 27 x + 6

4 x^{3} + x^{2} - 16 x - 4 = 0

(x^{2} - 3)^{2} = 9

What are the solutions to the equation -k^3+3k-2=0 ?
The solutions to the equation -k^3+3k-2=0 are k=1,k=-2
Find the zeros of -k^3+3k-2=0
The zeros of -k^3+3k-2=0 are k=1,k=-2