What are the solutions to the equation 4x^3+x^2-16x-4=0 ?

The solutions to the equation 4x^3+x^2-16x-4=0 are x=-1/4 ,x=-2,x=2

Find the zeros of 4x^3+x^2-16x-4=0

The zeros of 4x^3+x^2-16x-4=0 are x=-1/4 ,x=-2,x=2

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4 x^{3} + x^{2} - 16 x - 4 = 0

x = - \frac{1}{4}, x = - 2, x = 2

Decimal Notation

x = - 0.25, x = - 2, x = 2

Solution steps

4 x^{3} + x^{2} - 16 x - 4 = 0

Factor

4 x^{3} + x^{2} - 16 x - 4 : (4 x + 1) (x + 2) (x - 2)

(4 x + 1) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 1 = 0 or x + 2 = 0 or x - 2 = 0

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - \frac{1}{4}, x = - 2, x = 2

(x^{2} - 3)^{2} = 9

4 x^{3} - 24 x = 0

x^{3} + 6 x^{2} + 15 x - 25 = 0

x^{4} + 4 x^{2}

4 x^{3} + x^{7} = - 5

What are the solutions to the equation 4x^3+x^2-16x-4=0 ?
The solutions to the equation 4x^3+x^2-16x-4=0 are x=-1/4 ,x=-2,x=2
Find the zeros of 4x^3+x^2-16x-4=0
The zeros of 4x^3+x^2-16x-4=0 are x=-1/4 ,x=-2,x=2