What are the solutions to the equation x^3-3x^2+3x+7=0 ?

The solutions to the equation x^3-3x^2+3x+7=0 are x=-1,x=2+sqrt(3)i,x=2-sqrt(3)i

Find the zeros of x^3-3x^2+3x+7=0

The zeros of x^3-3x^2+3x+7=0 are x=-1,x=2+sqrt(3)i,x=2-sqrt(3)i

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x^{3} - 3 x^{2} + 3 x + 7 = 0

x = - 1, x = 2 + 3 i, x = 2 - 3 i

Solution steps

x^{3} - 3 x^{2} + 3 x + 7 = 0

Factor

x^{3} - 3 x^{2} + 3 x + 7 : (x + 1) (x^{2} - 4 x + 7)

(x + 1) (x^{2} - 4 x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{2} - 4 x + 7 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{2} - 4 x + 7 = 0 : x = 2 + 3 i, x = 2 - 3 i

The solutions are

x = - 1, x = 2 + 3 i, x = 2 - 3 i

- x^{3} + 6 x^{2} - 11 x + 6

3 x^{3} - 17 x^{2} + 18 x + 8 = 0

f, f x = 4 x^{3} - 6 x^{2}

x (2 x^{2} - 41) = 225

i x^{4} + x^{2} - i = 0

What are the solutions to the equation x^3-3x^2+3x+7=0 ?
The solutions to the equation x^3-3x^2+3x+7=0 are x=-1,x=2+sqrt(3)i,x=2-sqrt(3)i
Find the zeros of x^3-3x^2+3x+7=0
The zeros of x^3-3x^2+3x+7=0 are x=-1,x=2+sqrt(3)i,x=2-sqrt(3)i