What are the solutions to the equation 3x^4+5x^3-12x^2-20x=0 ?

The solutions to the equation 3x^4+5x^3-12x^2-20x=0 are x=0,x=-5/3 ,x=-2,x=2

Find the zeros of 3x^4+5x^3-12x^2-20x=0

The zeros of 3x^4+5x^3-12x^2-20x=0 are x=0,x=-5/3 ,x=-2,x=2

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3 x^{4} + 5 x^{3} - 12 x^{2} - 20 x = 0

x = 0, x = - \frac{5}{3}, x = - 2, x = 2

Decimal Notation

x = 0, x = - 1.66666 \dots, x = - 2, x = 2

Solution steps

3 x^{4} + 5 x^{3} - 12 x^{2} - 20 x = 0

Factor

3 x^{4} + 5 x^{3} - 12 x^{2} - 20 x : x (3 x + 5) (x + 2) (x - 2)

x (3 x + 5) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x + 5 = 0 or x + 2 = 0 or x - 2 = 0

Solve

3 x + 5 = 0 : x = - \frac{5}{3}

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - \frac{5}{3}, x = - 2, x = 2

x^{2} (2 x - 3)^{3} = 0

6 b^{3} - 9 b^{2} + 2 = 0

x^{3} + 8 x^{2} + 5 x - 14 = 0

4 x^{3} + 12 x^{2} - 4 x = 0

x^{6} - 14 x^{4} + 3 x^{2} - 42 = 0

What are the solutions to the equation 3x^4+5x^3-12x^2-20x=0 ?
The solutions to the equation 3x^4+5x^3-12x^2-20x=0 are x=0,x=-5/3 ,x=-2,x=2
Find the zeros of 3x^4+5x^3-12x^2-20x=0
The zeros of 3x^4+5x^3-12x^2-20x=0 are x=0,x=-5/3 ,x=-2,x=2