What are the solutions to the equation x^2(2x-3)^3=0 ?

The solutions to the equation x^2(2x-3)^3=0 are x=0,x= 3/2

Find the zeros of x^2(2x-3)^3=0

The zeros of x^2(2x-3)^3=0 are x=0,x= 3/2

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x^{2} (2 x - 3)^{3} = 0

x = 0, x = \frac{3}{2}

Decimal Notation

x = 0, x = 1.5

Solution steps

x^{2} (2 x - 3)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x - 3 = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = 0, x = \frac{3}{2}

6 b^{3} - 9 b^{2} + 2 = 0

x^{3} + 8 x^{2} + 5 x - 14 = 0

4 x^{3} + 12 x^{2} - 4 x = 0

x^{6} - 14 x^{4} + 3 x^{2} - 42 = 0

x, 2 = x^{4} + x^{2}

What are the solutions to the equation x^2(2x-3)^3=0 ?
The solutions to the equation x^2(2x-3)^3=0 are x=0,x= 3/2
Find the zeros of x^2(2x-3)^3=0
The zeros of x^2(2x-3)^3=0 are x=0,x= 3/2