What are the solutions to the equation 4x^3+12x^2-4x=0 ?

The solutions to the equation 4x^3+12x^2-4x=0 are x=0,x=(-3+sqrt(13))/2 ,x=(-3-sqrt(13))/2

Find the zeros of 4x^3+12x^2-4x=0

The zeros of 4x^3+12x^2-4x=0 are x=0,x=(-3+sqrt(13))/2 ,x=(-3-sqrt(13))/2

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4 x^{3} + 12 x^{2} - 4 x = 0

x = 0, x = \frac{- 3 + 13}{2}, x = \frac{- 3 - 13}{2}

Decimal Notation

x = 0, x = 0.30277 \dots, x = - 3.30277 \dots

Solution steps

4 x^{3} + 12 x^{2} - 4 x = 0

Factor

4 x^{3} + 12 x^{2} - 4 x : 4 x (x^{2} + 3 x - 1)

4 x (x^{2} + 3 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 3 x - 1 = 0

Solve

x^{2} + 3 x - 1 = 0 : x = \frac{- 3 + 13}{2}, x = \frac{- 3 - 13}{2}

The solutions are

x = 0, x = \frac{- 3 + 13}{2}, x = \frac{- 3 - 13}{2}

x^{6} - 14 x^{4} + 3 x^{2} - 42 = 0

x, 2 = x^{4} + x^{2}

x^{4} - x^{3} - 13 x^{2} + x + 12 = 0

s^{3} + 10.6 s^{2} + 7 s + 10 = 0

x^{4} - 4 x^{3} + 5 x^{2} - 2 x - 2

What are the solutions to the equation 4x^3+12x^2-4x=0 ?
The solutions to the equation 4x^3+12x^2-4x=0 are x=0,x=(-3+sqrt(13))/2 ,x=(-3-sqrt(13))/2
Find the zeros of 4x^3+12x^2-4x=0
The zeros of 4x^3+12x^2-4x=0 are x=0,x=(-3+sqrt(13))/2 ,x=(-3-sqrt(13))/2