What are the solutions to the equation 2x^3-11x^2+3x+36=0 ?

The solutions to the equation 2x^3-11x^2+3x+36=0 are x=3,x=-3/2 ,x=4

Find the zeros of 2x^3-11x^2+3x+36=0

The zeros of 2x^3-11x^2+3x+36=0 are x=3,x=-3/2 ,x=4

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2 x^{3} - 11 x^{2} + 3 x + 36 = 0

x = 3, x = - \frac{3}{2}, x = 4

Decimal Notation

x = 3, x = - 1.5, x = 4

Solution steps

2 x^{3} - 11 x^{2} + 3 x + 36 = 0

Factor

2 x^{3} - 11 x^{2} + 3 x + 36 : (x - 3) (2 x + 3) (x - 4)

(x - 3) (2 x + 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or 2 x + 3 = 0 or x - 4 = 0

Solve

x - 3 = 0 : x = 3

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x - 4 = 0 : x = 4

The solutions are

x = 3, x = - \frac{3}{2}, x = 4

3 x^{3} - 5 x^{2} + 148 x + 50

x^{3} - 9 x^{2} + x - 9 = 0

- x^{3} + 12 x = 0

81 x^{4} - 100 x^{2} = 0

y, x^{4} + y^{3} = 24

What are the solutions to the equation 2x^3-11x^2+3x+36=0 ?
The solutions to the equation 2x^3-11x^2+3x+36=0 are x=3,x=-3/2 ,x=4
Find the zeros of 2x^3-11x^2+3x+36=0
The zeros of 2x^3-11x^2+3x+36=0 are x=3,x=-3/2 ,x=4