What are the solutions to the equation -x^3+12x=0 ?

The solutions to the equation -x^3+12x=0 are x=0,x=-2sqrt(3),x=2sqrt(3)

Find the zeros of -x^3+12x=0

The zeros of -x^3+12x=0 are x=0,x=-2sqrt(3),x=2sqrt(3)

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- x^{3} + 12 x = 0

x = 0, x = - 23, x = 23

Decimal Notation

x = 0, x = - 3.46410 \dots, x = 3.46410 \dots

Solution steps

- x^{3} + 12 x = 0

Factor

- x^{3} + 12 x : - x (x + 23) (x - 23)

- x (x + 23) (x - 23) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 23 = 0 or x - 23 = 0

Solve

x + 23 = 0 : x = - 23

Solve

x - 23 = 0 : x = 23

The solutions are

x = 0, x = - 23, x = 23

81 x^{4} - 100 x^{2} = 0

y, x^{4} + y^{3} = 24

2 x^{4} + 4 x^{3} - 18 x^{2} - 36 x = 0

8 x^{3} + 50 x^{2} - 41 x + 7 = 0

9 x^{3} + 12 x^{2} + 4 x = 0

What are the solutions to the equation -x^3+12x=0 ?
The solutions to the equation -x^3+12x=0 are x=0,x=-2sqrt(3),x=2sqrt(3)
Find the zeros of -x^3+12x=0
The zeros of -x^3+12x=0 are x=0,x=-2sqrt(3),x=2sqrt(3)