What are the solutions to the equation roots 3x^3-5x^2+148x+50 ?

The solutions to the equation roots 3x^3-5x^2+148x+50 are x=-1/3 ,x=1+7i,x=1-7i

Find the zeros of roots 3x^3-5x^2+148x+50

The zeros of roots 3x^3-5x^2+148x+50 are x=-1/3 ,x=1+7i,x=1-7i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

3 x^{3} - 5 x^{2} + 148 x + 50

x = - \frac{1}{3}, x = 1 + 7 i, x = 1 - 7 i

Solution steps

3 x^{3} - 5 x^{2} + 148 x + 50

The roots are the intercepts with the x-axis

(y = 0)

3 x^{3} - 5 x^{2} + 148 x + 50 = 0

Factor

3 x^{3} - 5 x^{2} + 148 x + 50 : (3 x + 1) (x^{2} - 2 x + 50)

(3 x + 1) (x^{2} - 2 x + 50) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 1 = 0 or x^{2} - 2 x + 50 = 0

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

x^{2} - 2 x + 50 = 0 : x = 1 + 7 i, x = 1 - 7 i

The solutions are

x = - \frac{1}{3}, x = 1 + 7 i, x = 1 - 7 i

x^{3} - 9 x^{2} + x - 9 = 0

- x^{3} + 12 x = 0

81 x^{4} - 100 x^{2} = 0

y, x^{4} + y^{3} = 24

2 x^{4} + 4 x^{3} - 18 x^{2} - 36 x = 0

What are the solutions to the equation roots 3x^3-5x^2+148x+50 ?
The solutions to the equation roots 3x^3-5x^2+148x+50 are x=-1/3 ,x=1+7i,x=1-7i
Find the zeros of roots 3x^3-5x^2+148x+50
The zeros of roots 3x^3-5x^2+148x+50 are x=-1/3 ,x=1+7i,x=1-7i