What are the solutions to the equation (3x+2)(x^2-25)=0 ?

The solutions to the equation (3x+2)(x^2-25)=0 are x=-5,x=5,x=-2/3

Find the zeros of (3x+2)(x^2-25)=0

The zeros of (3x+2)(x^2-25)=0 are x=-5,x=5,x=-2/3

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(3 x + 2) (x^{2} - 25) = 0

x = - 5, x = 5, x = - \frac{2}{3}

Decimal Notation

x = - 5, x = 5, x = - 0.66666 \dots

Solution steps

(3 x + 2) (x^{2} - 25) = 0

Factor

(3 x + 2) (x^{2} - 25) : (x + 5) (x - 5) (3 x + 2)

(x + 5) (x - 5) (3 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 = 0 or x - 5 = 0 or 3 x + 2 = 0

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

The solutions are

x = - 5, x = 5, x = - \frac{2}{3}

6 x^{5} - 30 x^{4} = 0

6 x^{3} - 29 x^{2} - 6 x + 5

4 x^{3} - 8 x^{2} + x + 3 = 0

x^{3} + 2 x^{2} - x - 2

0 = 4 x^{3} - 12 x^{2} - 36 x

What are the solutions to the equation (3x+2)(x^2-25)=0 ?
The solutions to the equation (3x+2)(x^2-25)=0 are x=-5,x=5,x=-2/3
Find the zeros of (3x+2)(x^2-25)=0
The zeros of (3x+2)(x^2-25)=0 are x=-5,x=5,x=-2/3