What are the solutions to the equation 0=4x^3-12x^2-36x ?

The solutions to the equation 0=4x^3-12x^2-36x are x=0,x=(3+3sqrt(5))/2 ,x=(3-3sqrt(5))/2

Find the zeros of 0=4x^3-12x^2-36x

The zeros of 0=4x^3-12x^2-36x are x=0,x=(3+3sqrt(5))/2 ,x=(3-3sqrt(5))/2

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0 = 4 x^{3} - 12 x^{2} - 36 x

x = 0, x = \frac{3 + 3 5}{2}, x = \frac{3 - 3 5}{2}

Decimal Notation

x = 0, x = 4.85410 \dots, x = - 1.85410 \dots

Solution steps

0 = 4 x^{3} - 12 x^{2} - 36 x

Switch sides

4 x^{3} - 12 x^{2} - 36 x = 0

Factor

4 x^{3} - 12 x^{2} - 36 x : 4 x (x^{2} - 3 x - 9)

4 x (x^{2} - 3 x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} - 3 x - 9 = 0

Solve

x^{2} - 3 x - 9 = 0 : x = \frac{3 + 3 5}{2}, x = \frac{3 - 3 5}{2}

The solutions are

x = 0, x = \frac{3 + 3 5}{2}, x = \frac{3 - 3 5}{2}

(1 + x)^{10} = \frac{1000}{910}

3 (1 + g)^{4} = 3.7

a, a^{4} - t^{4} = 6 a^{2} t

3 x^{4} - 8 x^{2} = - 4

x^{2} 5 x + 1 = 3 x^{2} + 6

What are the solutions to the equation 0=4x^3-12x^2-36x ?
The solutions to the equation 0=4x^3-12x^2-36x are x=0,x=(3+3sqrt(5))/2 ,x=(3-3sqrt(5))/2
Find the zeros of 0=4x^3-12x^2-36x
The zeros of 0=4x^3-12x^2-36x are x=0,x=(3+3sqrt(5))/2 ,x=(3-3sqrt(5))/2