What are the solutions to the equation 4x^3-8x^2+x+3=0 ?

The solutions to the equation 4x^3-8x^2+x+3=0 are x=1,x=-1/2 ,x= 3/2

Find the zeros of 4x^3-8x^2+x+3=0

The zeros of 4x^3-8x^2+x+3=0 are x=1,x=-1/2 ,x= 3/2

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4 x^{3} - 8 x^{2} + x + 3 = 0

x = 1, x = - \frac{1}{2}, x = \frac{3}{2}

Decimal Notation

x = 1, x = - 0.5, x = 1.5

Solution steps

4 x^{3} - 8 x^{2} + x + 3 = 0

Factor

4 x^{3} - 8 x^{2} + x + 3 : (x - 1) (2 x + 1) (2 x - 3)

(x - 1) (2 x + 1) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x + 1 = 0 or 2 x - 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = 1, x = - \frac{1}{2}, x = \frac{3}{2}

x^{3} + 2 x^{2} - x - 2

0 = 4 x^{3} - 12 x^{2} - 36 x

(1 + x)^{10} = \frac{1000}{910}

3 (1 + g)^{4} = 3.7

a, a^{4} - t^{4} = 6 a^{2} t

What are the solutions to the equation 4x^3-8x^2+x+3=0 ?
The solutions to the equation 4x^3-8x^2+x+3=0 are x=1,x=-1/2 ,x= 3/2
Find the zeros of 4x^3-8x^2+x+3=0
The zeros of 4x^3-8x^2+x+3=0 are x=1,x=-1/2 ,x= 3/2