What is the answer to log_{x}(1/32)=-10 ?

The answer to log_{x}(1/32)=-10 is x=e^{(ln(2))/2}

Solve for x: log_{x}(1/32)=-10

The solution is x=e^{(ln(2))/2}

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lo g_{x} (\frac{1}{32}) = - 10

x = e^{\frac{l n ( 2 )}{2}}

Decimal

x = 1.41421 \dots

Solution steps

lo g_{x} (\frac{1}{32}) = - 10

Apply log rules

\frac{ln ( \frac{1}{32} )}{ln ( x )} = - 10

Multiply both sides by

ln (x)

\frac{ln ( \frac{1}{32} )}{ln ( x )} ln (x) = - 10 ln (x)

Apply log rules

x = e^{\frac{l n ( 2 )}{2}}

Verify Solutions:

x = e^{\frac{l n ( 2 )}{2}}

True

The solution is

x = e^{\frac{l n ( 2 )}{2}}

lo g_{10} (x) = 4

ln (5 x + 7) = 8

y, ln (y - 1) - ln (x) = x + ln (x)

ln (x - \frac{1}{2}) + ln (2) = 2 ln (x)

lo g_{10} (- x) + lo g_{10} (1 - 2 x) = 1

What is the answer to log_{x}(1/32)=-10 ?
The answer to log_{x}(1/32)=-10 is x=e^{(ln(2))/2}
Solve for x: log_{x}(1/32)=-10
The solution is x=e^{(ln(2))/2}