What is the answer to log_{4}(x^2-15x)=2 ?

The answer to log_{4}(x^2-15x)=2 is x=16,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{4}(x^2-15x)=2

lo g_{4} (x^{2} - 15 x) = 2

x = 16, x = - 1

Solution steps

lo g_{4} (x^{2} - 15 x) = 2

Apply log rules

x^{2} - 15 x = 16

Solve

x^{2} - 15 x = 16 : x = 16, x = - 1

x = 16, x = - 1

lo g_{2} (5 y^{2} + 2 y - 8) = 4

lo g_{10} (4) + lo g_{10} (5 x) = 2

lo g_{\frac{1}{3}} (x) = - 4

\frac{x}{2 - lo g _{2} ( x )} = 0

lo g_{7} ((x - 1)^{2}) = 0

What is the answer to log_{4}(x^2-15x)=2 ?
The answer to log_{4}(x^2-15x)=2 is x=16,x=-1
Solve for x: log_{4}(x^2-15x)=2
The solution is x=16,x=-1