What is the answer to log_{2}(5y^2+2y-8)=4 ?

The answer to log_{2}(5y^2+2y-8)=4 is y=2,y=-12/5

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log_{2}(5y^2+2y-8)=4

lo g_{2} (5 y^{2} + 2 y - 8) = 4

y = 2, y = - \frac{12}{5}

Decimal

y = 2, y = - 2.4

Solution steps

lo g_{2} (5 y^{2} + 2 y - 8) = 4

Apply log rules

5 y^{2} + 2 y - 8 = 16

Solve

5 y^{2} + 2 y - 8 = 16 : y = 2, y = - \frac{12}{5}

y = 2, y = - \frac{12}{5}

lo g_{10} (4) + lo g_{10} (5 x) = 2

lo g_{\frac{1}{3}} (x) = - 4

\frac{x}{2 - lo g _{2} ( x )} = 0

lo g_{7} ((x - 1)^{2}) = 0

3 - lo g_{10} (x + 2) = 5

What is the answer to log_{2}(5y^2+2y-8)=4 ?
The answer to log_{2}(5y^2+2y-8)=4 is y=2,y=-12/5
Solve for y: log_{2}(5y^2+2y-8)=4
The solution is y=2,y=-12/5