What is the answer to ln(x+12)-ln(x)=5 ?

The answer to ln(x+12)-ln(x)=5 is x=(12)/(e^5-1)

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ln(x+12)-ln(x)=5

ln (x + 12) - ln (x) = 5

x = \frac{12}{e ^{5} - 1}

Decimal

x = 0.08140 \dots

Solution steps

ln (x + 12) - ln (x) = 5

Add

ln (x)

to both sides

ln (x + 12) - ln (x) + ln (x) = 5 + ln (x)

Simplify

ln (x + 12) = 5 + ln (x)

Apply log rules

x + 12 = e^{5} x

Solve

x + 12 = e^{5} x : x = \frac{12}{e ^{5} - 1}

x = \frac{12}{e ^{5} - 1}

Verify Solutions:

x = \frac{12}{e ^{5} - 1}

True

The solution is

x = \frac{12}{e ^{5} - 1}

lo g_{2} (- x) = - 5

\frac{( 1 - ln ( x ) )}{x ^{2}} = 0

ln (x^{2}) = - 1

x, 2 x ln (x) + x = 0

lo g_{216} (x) = - \frac{1}{3}

What is the answer to ln(x+12)-ln(x)=5 ?
The answer to ln(x+12)-ln(x)=5 is x=(12)/(e^5-1)
Solve for x: ln(x+12)-ln(x)=5
The solution is x=(12)/(e^5-1)