What is the answer to 7log_{6}(4x)+5=-2 ?

The answer to 7log_{6}(4x)+5=-2 is x= 1/24

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7log_{6}(4x)+5=-2

7 lo g_{6} (4 x) + 5 = - 2

x = \frac{1}{24}

Decimal

x = 0.04166 \dots

Solution steps

7 lo g_{6} (4 x) + 5 = - 2

Move

5

to the right side

7 lo g_{6} (4 x) = - 7

Divide both sides by

7

lo g_{6} (4 x) = - 1

Apply log rules

4 x = \frac{1}{6}

Solve

4 x = \frac{1}{6} : x = \frac{1}{24}

x = \frac{1}{24}

Verify Solutions:

x = \frac{1}{24}

True

The solution is

x = \frac{1}{24}

2 lo g_{10} (x) - lo g_{10} (x - 16) = 2

lo g_{10} (x^{5}) = (lo g_{10} (x^{5}))^{3}

lo g_{10} (- 2 x) + lo g_{10} (6) = 1

lo g_{10} (3 x) = 3 x

lo g_{x} (512) = \frac{3}{2}

What is the answer to 7log_{6}(4x)+5=-2 ?
The answer to 7log_{6}(4x)+5=-2 is x= 1/24
Solve for x: 7log_{6}(4x)+5=-2
The solution is x= 1/24