What is the answer to log_{sqrt(3)}(x^2-5x-3)=2 ?

The answer to log_{sqrt(3)}(x^2-5x-3)=2 is x=6,x=-1

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log_{sqrt(3)}(x^2-5x-3)=2

lo g_{3} (x^{2} - 5 x - 3) = 2

x = 6, x = - 1

Solution steps

lo g_{3} (x^{2} - 5 x - 3) = 2

Apply log rules

x^{2} - 5 x - 3 = 3

Solve

x^{2} - 5 x - 3 = 3 : x = 6, x = - 1

x = 6, x = - 1

lo g_{10} (x - 1) = 0

lo g_{3} (x^{2} - 5 x + 9) = 2

y, lo g_{y} (\frac{1}{x}) = - 2

lo g_{2} (x^{2} + 4 x + 3) = 3

lo g_{2 x} (3 x^{2} + 9 x - 14) = 2

What is the answer to log_{sqrt(3)}(x^2-5x-3)=2 ?
The answer to log_{sqrt(3)}(x^2-5x-3)=2 is x=6,x=-1
Solve for x: log_{sqrt(3)}(x^2-5x-3)=2
The solution is x=6,x=-1