What is the answer to ln(8x)+3=ln(2x+6) ?

The answer to ln(8x)+3=ln(2x+6) is x= 3/(4e^3-1)

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ln(8x)+3=ln(2x+6)

ln (8 x) + 3 = ln (2 x + 6)

x = \frac{3}{4 e ^{3} - 1}

Decimal

x = 0.03781 \dots

Solution steps

ln (8 x) + 3 = ln (2 x + 6)

Apply log rules

8 x e^{3} = 2 x + 6

Solve

8 x e^{3} = 2 x + 6 : x = \frac{3}{4 e ^{3} - 1}

x = \frac{3}{4 e ^{3} - 1}

Verify Solutions:

x = \frac{3}{4 e ^{3} - 1}

True

The solution is

x = \frac{3}{4 e ^{3} - 1}

lo g_{7} (\frac{3 x}{4} - 2) = 0

lo g_{4} (x - 4) = 3

lo g_{0.4} (20 x) = - 1

lo g_{4} (2 x - 7) = 3

ln (x + a^{2} + x^{2})

What is the answer to ln(8x)+3=ln(2x+6) ?
The answer to ln(8x)+3=ln(2x+6) is x= 3/(4e^3-1)
Solve for x: ln(8x)+3=ln(2x+6)
The solution is x= 3/(4e^3-1)