What is the answer to log_{7}((3x)/4-2)=0 ?

The answer to log_{7}((3x)/4-2)=0 is x=4

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log_{7}((3x)/4-2)=0

lo g_{7} (\frac{3 x}{4} - 2) = 0

x = 4

Solution steps

lo g_{7} (\frac{3 x}{4} - 2) = 0

Apply log rules

\frac{3 x}{4} - 2 = 7^{0}

Multiply both sides by

4

\frac{3 x}{4} \cdot 4 - 2 \cdot 4 = 7^{0} \cdot 4

Simplify

3 x - 8 = 4

Solve

3 x - 8 = 4 : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

lo g_{4} (x - 4) = 3

lo g_{0.4} (20 x) = - 1

lo g_{4} (2 x - 7) = 3

ln (x + a^{2} + x^{2})

ln (x) - ln (x^{2}) = \frac{1}{2}

What is the answer to log_{7}((3x)/4-2)=0 ?
The answer to log_{7}((3x)/4-2)=0 is x=4
Solve for x: log_{7}((3x)/4-2)=0
The solution is x=4